4t^2/5=11t/5+13/10

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Solution for 4t^2/5=11t/5+13/10 equation:


t in (-oo:+oo)

(4*t^2)/5 = (11*t)/5+13/10 // - (11*t)/5+13/10

(4*t^2)/5-((11*t)/5)-(13/10) = 0

(4*t^2)/5+(-11/5)*t-13/10 = 0

4/5*t^2-11/5*t-13/10 = 0

DELTA = (-11/5)^2-(-13/10*4/5*4)

DELTA = 9

DELTA > 0

t = (9^(1/2)+11/5)/(4/5*2) or t = (11/5-9^(1/2))/(4/5*2)

t = 13/4 or t = -1/2

t in { -1/2, 13/4 }

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